Commutative Presemifields and Semifields: Difference between revisions

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=Introduction=
=Introduction=
A <span class="definition">semifields</span> os a romg with left and right distributivity and with no zero divisor.
A <span class="definition">semifields</span> is a ring with left and right distributivity and with no zero divisor.
A presemifield with a multiplicative identity is called a <span class="definition">semifield</span>.
A presemifield with a multiplicative identity is called a <span class="definition">semifield</span>.
Any finite presemifield can be represented by <math>\mathbb{S}=(\mathbb{F}_{p^n},+,\star)</math>,
Any finite presemifield can be represented by <math>\mathbb{S}=(\mathbb{F}_{p^n},+,\star)</math>,

Revision as of 10:26, 29 August 2019

Introduction

A semifields is a ring with left and right distributivity and with no zero divisor. A presemifield with a multiplicative identity is called a semifield. Any finite presemifield can be represented by , for a prime, a positive integer, additive group and Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle x\star y} multiplication linear in each variable.

Two presemifields and Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \mathbb {S} _{2}=(\mathbb {F} _{p^{n}},+,\circ )} are called isotopic if there exist three linear permutation Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle T,M,N} of such that Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle T(x\star y)=M(x)\circ N(y)} , for any . If Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle M=N} then they are called strongly isotopic. Each commutative presemifields of odd order defines a planar DO polynomial and viceversa:

  • given let Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle F_{\mathcal {S}}(x)={\frac {1}{2}}(x\star x)} ;
  • given let Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \mathbb {S} _{F}=(\mathbb {F} _{p^{n}},+,\star )} defined by .

Hence two quadratic planar functions are isotopic equivalent if their corresponding presemifields are isotopic. Moreover, we have:

  • are CCZ-equivalent if and only if Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \mathbb {S} _{F},\mathbb {S} _{F'}} are strongly isotopic;
  • for odd, isotopic coincides with strongly isotopic;
  • if are isotopic equivalent, then there exists a linear map such that is EA-equivalent to Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle F(x+L(x))-F(x)-F(L(x))} .